Asked by naomi
A particle at rest undergoes an acceleration
of 2.1 m/s2 to the right and 5 m/s2 up.
a) What is its speed after 7.9 s?
Answer in units of m/s.
of 2.1 m/s2 to the right and 5 m/s2 up.
a) What is its speed after 7.9 s?
Answer in units of m/s.
Answers
Answered by
bobpursley
horizontal:
2.1*7.9= ...
vertical:
5*7.9=....
speed= sqrt(horizontal^2+ vertical^2)
2.1*7.9= ...
vertical:
5*7.9=....
speed= sqrt(horizontal^2+ vertical^2)
Answered by
Anonymous
56.09
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