Question
A particle at rest undergoes an acceleration of 2.5 m/s^2 to the right and 3.2 m/s^2 up. What is its speed after 5.9s? Answer in m/s
Answers
drwls
The magnitude of the acceleration is
a = sqrt[2.5^2 + 3.2^2] = 4.06 m/s^2,
since the two directions are perpendicular.
The speed after 5.9s is 5.9 a
You do the multiplication.
a = sqrt[2.5^2 + 3.2^2] = 4.06 m/s^2,
since the two directions are perpendicular.
The speed after 5.9s is 5.9 a
You do the multiplication.