Asked by kevin
A ball of mass 0.35 kg is fired with velocity 157 m/s into the barrel of a spring gun of mass 1.8 kg initially at rest on a frictionless surface. The ball sticks in the barrel at the point of maximum compression of the spring. No energy is lost to friction. What fraction of the ball's initial kinetic energy is stored in the spring?
Answers
Answered by
drwls
Use the law of conservation of momentum to compute the final velocity of the gun and ball, Vf.
0.35*157 = (1.8 + 0.35)*Vf
Vf = 25.56 m/s
The final kinetic energy is (25.56/157)^2 = 2.6% of the initial KE
The rest, 97.4%, is stored in the spring, if there was no friction.
0.35*157 = (1.8 + 0.35)*Vf
Vf = 25.56 m/s
The final kinetic energy is (25.56/157)^2 = 2.6% of the initial KE
The rest, 97.4%, is stored in the spring, if there was no friction.
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