Question
A ball is fired from the ground with an initial speed of 1.70 x 103 m/s (approximately five times the speed of sound) at an initial angle of 55.0° to the horizontal. Neglecting air resistance, find
a. the ball’s horizontal range.
b. the amount of time the ball is in motion
a. the ball’s horizontal range.
b. the amount of time the ball is in motion
Answers
Anonymous
I think you mean initial speed =1.70 * 10^3 m/s
Vertical problem:
Vi = 1.70 * 10^3 sin 55 = 1.39 * 10^3
v = Vi - g t
at top v = 0
t at top = 1.39*10^3 / 9.81 = 1.5 * 10^2 seconds upward ( so total time in air = 300 seconds)
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Horizontal problem:
u = 1700 cos 55 = 975 m/s
for 300 seconds so range = 975*300 = 292500 meters = 293 km
Vertical problem:
Vi = 1.70 * 10^3 sin 55 = 1.39 * 10^3
v = Vi - g t
at top v = 0
t at top = 1.39*10^3 / 9.81 = 1.5 * 10^2 seconds upward ( so total time in air = 300 seconds)
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Horizontal problem:
u = 1700 cos 55 = 975 m/s
for 300 seconds so range = 975*300 = 292500 meters = 293 km
Anonymous
By the way anything shaped like a ball would burn up at that speed.