Vo = 1520m/s[35.5o]
Yo = 1520*sin35.5 = 883 m/s.
KE = 0.5M*Yo^2 = 0.5*25*883^2
KE = 0.5M*Yo^2 = 0.5*25*883^2=9,746,113
J.
PE = KE = Mg*h = 9,746,113
25+9.8*h = 9,746,113
245h = 9,746,113
h = 39,780 m.
A 25 kg cannon ball is fired from a cannon
with muzzle speed of 1520 m/s at an angle of
35.5
◦ with the horizontal.
The acceleration of gravity is 9.8 m/s
2
.
Use conservation of mechanical energy to
find the maximum height reached by first ball.
Answer in units of m.
I AM CONFUSED HOW TO SET UP THE PROBLEM. PLEASE HELP
1 answer
1 answer