Asked by Anonymous
A cannon ball is fired horizontally with velocity of 15m from the top of a cliff 90m high.after how many seconds will it hit the foot of the cliff(a)time (b)at what distance from the foot of the cliff will it strike.
Answers
Answered by
Henry
Xo = 15 m/s.
h = 90 m.
g = 9.8 m/s^2
a. h = 0.5g*t^2 = 90 m. Solve for t.
b. Dx = Xo * t
h = 90 m.
g = 9.8 m/s^2
a. h = 0.5g*t^2 = 90 m. Solve for t.
b. Dx = Xo * t
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