Question
A cannon ball is fired horizontally with velocity of 15m from the top of a cliff 90m high.after how many seconds will it hit the foot of the cliff(a)time (b)at what distance from the foot of the cliff will it strike.
Answers
Xo = 15 m/s.
h = 90 m.
g = 9.8 m/s^2
a. h = 0.5g*t^2 = 90 m. Solve for t.
b. Dx = Xo * t
h = 90 m.
g = 9.8 m/s^2
a. h = 0.5g*t^2 = 90 m. Solve for t.
b. Dx = Xo * t
Related Questions
A cannon ball is fired horizontally with a velocity of 50m/s from the top of a cliff 90m high,after...
A cannon ball is fired horizontally with a velocity of 50m/s from the top of a cliff 90m high,after...
A cannon ball is fired horizontally with a velocity of 50m/s from the top of a cliff 90m high,after...
A cannon ball is fired horizontally from a cannon that is 40.7m above the ground. The initial veloci...