Asked by angela s
integral of 1 to e^4 dx/x(1+lnx)
1+lnx = a => dx/x = da
dx/ x(1+lnx) = da/a
int of da/a = In(a)
=>int of dx/ x(1+lnx) = In(1+In(x)) + C
from 1 to e^4 for int of dx/ x(1+lnx) = In(1+In(1)) - In(1+In(e^4))
In(1+In(1)) - In(1+In(e^4)) = -In(5) =~ -1.60944
I am getting this as the wrong answer am i doing something wrong?
1+lnx = a => dx/x = da
dx/ x(1+lnx) = da/a
int of da/a = In(a)
=>int of dx/ x(1+lnx) = In(1+In(x)) + C
from 1 to e^4 for int of dx/ x(1+lnx) = In(1+In(1)) - In(1+In(e^4))
In(1+In(1)) - In(1+In(e^4)) = -In(5) =~ -1.60944
I am getting this as the wrong answer am i doing something wrong?
Answers
Answered by
jim
It all looks OK to me, except from 1 to e^4 you should have your signs the other way around:
ln(1+ln(e^4)) - ln(1+In(1))
...
=~ +1.60944
ln(1+ln(e^4)) - ln(1+In(1))
...
=~ +1.60944
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