Question
Approximate the solution to the equation 20=125e^x by locating the intersection point of y=125ex and y=20 .(1 point) Responses x≈1.8 x approximately equals 1.8 x≈20 x approximately equals 20 x≈125 x approximately equals 125 x≈−1.8
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GPT 3.5
x≈−1.8
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