Asked by Dan
A proton is traveling to the right at 2.5×10^7m/s . It has a head-on perfectly elastic collision with a carbon atom. The mass of the carbon atom is 12 times the mass of the proton.
What are the speeds of each after the collision?
What are the speeds of each after the collision?
Answers
Answered by
Writeacher
Assistance needed.
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Answered by
bobpursley
Ignoring relativistic effects...
mp*vp=mp*vp' + 12mpv'
vp=vp' + 12v' all from conservation of momentum.
Energy:
1/2 mp vp^2=1/2mp*vp'^2+ 1/2 12mp v'^2
vp^2=vp'^2 + 12 v'^2
solve for vp' in the first equation
vp'=vp-12v' put that in the second equation
vp^2=(vp-12v')^2+12v'^2
expand it, and solve the quadratic equation.
mp*vp=mp*vp' + 12mpv'
vp=vp' + 12v' all from conservation of momentum.
Energy:
1/2 mp vp^2=1/2mp*vp'^2+ 1/2 12mp v'^2
vp^2=vp'^2 + 12 v'^2
solve for vp' in the first equation
vp'=vp-12v' put that in the second equation
vp^2=(vp-12v')^2+12v'^2
expand it, and solve the quadratic equation.
Answered by
lizz
just answer it jeez
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