Asked by Chantelle

A proton is traveling at 2.3E6 m/s in a circular path in 0.75 T magnetic field. What is the magnitude of the force of the proton?

9 years ago

Answered by bobpursley

force=q*v*B

9 years ago

Answered by Scott

F = charge * velocity * field strength

F = 2.76E-13 N

9 years ago

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