If a car accelerates from rest at a constant 5.5m/s^2, how long will be required to reach 28m/s?

Answer 1

ok so you use the First kinematic relation:

V=u+at

where v is the final velocity
u is the initial velocity
a is acceleration
t is time taken

So, for this question
v= 28m/s
u= 0 m/s (because car was at rest)
a= 5.5m/s^2
t= what you need to find out

Solve for t and substitute the values

t= (v-u)/a

Answer 2

t=(v-u)/a

t= (28m/s- 0m/s)/5.5m/s^2
= (28m/s)/5.5m/s^2
t= 5.09s

Answer 3

153.9725