Asked by Glorious
A label on a bottle of HCL has the following information density 1.134gm cubic percentage purity 37%.determine the volume of the stock acid containing one mole of HCL ,explain how a molar solution can be prepared using the volume of stock acid obtained
Answers
Answered by
GPT 3.5
To determine the volume of the stock acid containing one mole of HCl, we can use the formula:
Volume = Mass / Density
First, we need to calculate the mass of HCl in the stock acid. The percentage purity of 37% means that there are 37 grams of HCl in every 100 grams of stock acid. So, the mass of HCl can be calculated as:
Mass of HCl = (Percentage purity / 100) * Mass of stock acid
= (37 / 100) * 1.134 g/cm^3
= 0.41958 g/cm^3
Next, we can calculate the volume of the stock acid containing one mole of HCl using the molar mass of HCl. The molar mass of HCl is approximately 36.5 g/mol. Therefore:
Volume = Mass of HCl / Density
= (0.41958 g/cm^3) / (36.5 g/mol)
≈ 0.0115 cm^3/mol (rounded to four decimal places)
Now, to prepare a molar solution using the volume of stock acid obtained, we need to dilute the stock acid to a specific volume and concentration. Since we know the volume of stock acid needed to make one mole of HCl is 0.0115 cm^3, we can follow these steps:
1. Calculate the volume of stock acid required to make the desired concentration of molar solution. For example, if you want to prepare 1 liter (1000 cm^3) of a 1 molar (1M) solution, we can use the formula:
Volume of stock acid = (Volume of molar solution * Molar concentration) / (Volume of stock acid containing one mole of HCl)
= (1000 cm^3 * 1M) / (0.0115 cm^3/mol)
≈ 86,956.52 cm^3 (rounded to two decimal places)
So, you would need approximately 86,956.52 cm^3 or 86.96 liters of the stock acid to prepare 1 liter of a 1M HCl solution.
2. Take the calculated volume of stock acid and add it to a suitable container.
3. Add distilled water to the container to reach the final desired volume of the molar solution (e.g., 1 liter).
4. Mix the solution thoroughly until it is homogenous.
Now, you have prepared a molar solution of HCl using the volume of stock acid obtained.
Volume = Mass / Density
First, we need to calculate the mass of HCl in the stock acid. The percentage purity of 37% means that there are 37 grams of HCl in every 100 grams of stock acid. So, the mass of HCl can be calculated as:
Mass of HCl = (Percentage purity / 100) * Mass of stock acid
= (37 / 100) * 1.134 g/cm^3
= 0.41958 g/cm^3
Next, we can calculate the volume of the stock acid containing one mole of HCl using the molar mass of HCl. The molar mass of HCl is approximately 36.5 g/mol. Therefore:
Volume = Mass of HCl / Density
= (0.41958 g/cm^3) / (36.5 g/mol)
≈ 0.0115 cm^3/mol (rounded to four decimal places)
Now, to prepare a molar solution using the volume of stock acid obtained, we need to dilute the stock acid to a specific volume and concentration. Since we know the volume of stock acid needed to make one mole of HCl is 0.0115 cm^3, we can follow these steps:
1. Calculate the volume of stock acid required to make the desired concentration of molar solution. For example, if you want to prepare 1 liter (1000 cm^3) of a 1 molar (1M) solution, we can use the formula:
Volume of stock acid = (Volume of molar solution * Molar concentration) / (Volume of stock acid containing one mole of HCl)
= (1000 cm^3 * 1M) / (0.0115 cm^3/mol)
≈ 86,956.52 cm^3 (rounded to two decimal places)
So, you would need approximately 86,956.52 cm^3 or 86.96 liters of the stock acid to prepare 1 liter of a 1M HCl solution.
2. Take the calculated volume of stock acid and add it to a suitable container.
3. Add distilled water to the container to reach the final desired volume of the molar solution (e.g., 1 liter).
4. Mix the solution thoroughly until it is homogenous.
Now, you have prepared a molar solution of HCl using the volume of stock acid obtained.