Question

A label on o bottle of HCL has the following information density 1.134grams per metre cubic and percentage purity 37% find the number of moles of HCL in 1centimetre cubic of the stock solution,determine the molarity of the stock solution , determine the volume of the stock acid containing one mole of HCL

Answer 1

To find the number of moles of HCl in 1 cm^3 of the stock solution, we need to calculate the mass of HCl in 1 cm^3 and then convert it to moles.

Given:
Information density: 1.134 grams/m^3
Percentage purity: 37%

First, let's calculate the mass of HCl in 1 cm^3 of the solution:
Mass of HCl in 1 cm^3 = Information density * 1 cm^3
= 1.134 grams/m^3 * 1 cm^3
= 1.134 grams

Next, let's find the percentage of HCl in the stock solution:
Percentage of HCl in the stock solution = Percentage purity
= 37%

Now, we can calculate the mass of pure HCl in the stock solution:
Mass of pure HCl = Mass of HCl in 1 cm^3 / (Percentage of HCl in the stock solution / 100)
= 1.134 grams / (37/100)
= 1.134 grams / 0.37
= 3.068 grams

To convert the mass of HCl to moles, we need to know the molar mass of HCl. The molar mass of HCl is 36.461 g/mol.

Now, let's calculate the number of moles of HCl in 1 cm^3 of the stock solution:
Number of moles of HCl = Mass of pure HCl / Molar mass of HCl
= 3.068 grams / 36.461 g/mol
≈ 0.084 mol

The molarity of the stock solution is given by the number of moles of solute (HCl) divided by the volume of the solution in liters:
Molarity = Number of moles of HCl / Volume of the stock solution (in liters)
= 0.084 mol / 1 L
≈ 0.084 M

To determine the volume of the stock acid containing one mole of HCl, we need to use the molarity of the stock solution and the definition of molarity. The definition of molarity is moles of solute per liter of solution, so the volume of solution containing one mole of solute is 1 liter (or 1000 cm^3).

Therefore, the volume of the stock acid containing one mole of HCl is 1 cm^3.