Question

A circle has the equation x2−12x+27=−y2+8y.
What is the equation of the circle in standard form, the location of its center, and the length of its radius?

Responses
The equation of the circle is (x−6)2+(y−4)2=25; the center is at (6,4), and the radius is 5 units.
The equation of the circle is (x−6)2+(y−4)2=25; the center is at (−6,−4), and the radius is 5 units.
The equation of the circle is (x−6)2+(y−4)2=5; the center is at (−6,−4), and the radius is 5√ units.
The equation of the circle is (x−6)2+(y−4)2=5; the center is at (6,4), and the radius is 5√ units.

Answer 1

The equation of the circle in standard form is (x−6)2+(y−4)2=25. The center of the circle is at (6,4) and the radius is 5 units.