Question

A circle has the equation x2+12y+22x+y2−167=0.
What is the equation of the circle in standard form?

Responses
(x−11)2+(y−6)2=184
(x+11)2+(y+6)2=324
(x−11)2+(y−6)2=324
(x+11)2+(y+6)2=184

Answer 1

The correct equation of the circle in standard form is (x+11)2+(y+6)2=324.