Asked by mary
Find the standard form of the equation of the circle with the given characteristics.
Center: (5, -2); point on circle: (-3, -4)
Center: (5, -2); point on circle: (-3, -4)
Answers
Answered by
Reiny
You know the equation must have the form
(x-5)^2 + (y+2)^2= r^2
plug in the given point to find r^2 and you are done.
(x-5)^2 + (y+2)^2= r^2
plug in the given point to find r^2 and you are done.
Answered by
Yalikejazz01
Hey i got 68 as the radius. So im guessing 68 is the answer right?
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