Question
Find the standard form of the equation of the circle with the given characteristics.
Center: (5, -2); point on circle: (-3, -4)
Center: (5, -2); point on circle: (-3, -4)
Answers
You know the equation must have the form
(x-5)^2 + (y+2)^2= r^2
plug in the given point to find r^2 and you are done.
(x-5)^2 + (y+2)^2= r^2
plug in the given point to find r^2 and you are done.
Hey i got 68 as the radius. So im guessing 68 is the answer right?
Related Questions
Write the equation of the circle in standard form. Find the center, radius, intercepts, and graph th...
Let the equation of a circle be x^2+y^2-14x+8y+56
a. Find the standard form of the circle
b. F...
find the standard form of the equation of the circle with a center at (6, -3) and a point on the cir...
A circle has the equation x2−12x+27=−y2+8y.
What is the equation of the circle in standard form, th...