Question
determined the area enclosed between each pair of curves below y=x and y=x^3
Answers
Answered by
oobleck
Bogus yet again!
The curves are both odd and so the area above the x-axis is the same as that below the x-axis. So the algebraic area
∫[from -1 to 1] (x^3 - x) dx = 0
We can get the geometric area using ( since y=x is the upper curve!)
A = 2∫[0..1] (x - x^3) dx = 1/2
The curves are both odd and so the area above the x-axis is the same as that below the x-axis. So the algebraic area
∫[from -1 to 1] (x^3 - x) dx = 0
We can get the geometric area using ( since y=x is the upper curve!)
A = 2∫[0..1] (x - x^3) dx = 1/2
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