Asked by alex
Find the area enclosed by the curve
x = (t^2)-2t, y = (t)^(1/2) and the y-axis.
x = (t^2)-2t, y = (t)^(1/2) and the y-axis.
Answers
Answered by
Steve
a = ∫[0,2] √t (2t-2) dt = 8√2/15
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