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Asked by alex

Find the area enclosed by the curve
x = (t^2)-2t, y = (t)^(1/2) and the y-axis.
8 years ago

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Answered by Steve
a = ∫[0,2] √t (2t-2) dt = 8√2/15
8 years ago
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Find the area enclosed by the curve
x = (t^2)-2t, y = (t)^(1/2) and the y-axis.

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