Question
find the area enclosed between the following curves:- Y= lnx and y= -2x+3 and the ordinate x=3
Answers
Steve
The graphs intersect at x = 1.35, so we want
Int(ln x - (3-2x))[1.35,3]
= (xlnx - x - 3x + x^2)[1.35,3]
= xlnx - 4x + x^2 [1.35,3]
= 0.296 - (-3.172) = 3.468
Int(ln x - (3-2x))[1.35,3]
= (xlnx - x - 3x + x^2)[1.35,3]
= xlnx - 4x + x^2 [1.35,3]
= 0.296 - (-3.172) = 3.468
anonymous
hi, thanks for the answer but the question asks for it to be solved in integration form- is this right?