Question

A projectivle is launched with an initial speed of 40m/s at an angle of 35 degree above the horizontal. The projectitile lands on a hillside 4s later. negelct air friction.
a.What is the straight-line distance form where the prjectile was launched to where it hits its target?note that the hill may slope up or down from the launch point. Thank you

Answer 1

Consider horizontal and vertical motions separately.

Horizontal:
velocity, v0 = 40*cos(35°) m/s
Time, t = 4 s.
Horizontal distance, H = v0*t m.

Vertical:
initial velocity, v0 = 40 sin(35°) m/s
acceleration, a = -g m/s/s/
Time, t = 4 s.
vertical distance, V = v0*t+(1/2)at²

Straignt line distance
=√(H²+V²)

Check my thinking and calculations.