Question
write the general form of the equation of the lines throught the point
(a) parallel to the given line and (b) perpendicular to the given point
point- (2,1)
line- 4x-2y=3
(a) parallel to the given line and (b) perpendicular to the given point
point- (2,1)
line- 4x-2y=3
Answers
Given a line
L : Ax+By+C=0 and a point P1(x1,y1),
The line passing through P1 and parallel to L is given by:
A(x-x1)+B(y-y1)=0
The line passing through P1 and perpendicular to L is given by:
B(x-x1)-A(y-y1)=0
Post if you need more help.
L : Ax+By+C=0 and a point P1(x1,y1),
The line passing through P1 and parallel to L is given by:
A(x-x1)+B(y-y1)=0
The line passing through P1 and perpendicular to L is given by:
B(x-x1)-A(y-y1)=0
Post if you need more help.
yes i need help can you solve it out then i will ask you questions from then
I will give you an example how to apply those formulas, and would appreciate if you could show me the solution to the posted question. I will be glad to check the answer for you.
Here we go.
Given
L : 4x + 3y = 2, and
P1 : (5,2)
a. Find the line L1 passing through P1 and parallel to L, and
b. L2 passing through P1 and perpendicular to L.
a. Line L1 parallel to L
L : 4x + 3y -2 = 0, P1(5,2)
A=4, B=3, C= -2, x1=5, y1=2
L1 : A(x-x1)+B(y-y1)=0
L1 : 4(x-5)+3(y-2)=0
L1 : 4x -20 + 3y -6 =0
L1 : 4x + 3y - 26 =0
check: substitute x=5, y=2
4(5)+3(2)-26 = 20+6-26=0
Therefore L1 passes through P1.
Slope: m = -4/3
b. Line L2 perpendicular to L
L : 4x + 3y -2 = 0, P1(5,2)
A=4, B=3, C= -2, x1=5, y1=2
L2 : B(x-x1)-A(y-y1)=0
L2 : 3(x-5) - 4(y-2) = 0
L2 : 3x -15 - 4y + 8 = 0
L2 : 3x - 4y - 7 = 0
check: substitute x=5, y=2
L2 : 3(5)-4*2-7 = 15-8-7=0 L2 passes through P1.
Here we go.
Given
L : 4x + 3y = 2, and
P1 : (5,2)
a. Find the line L1 passing through P1 and parallel to L, and
b. L2 passing through P1 and perpendicular to L.
a. Line L1 parallel to L
L : 4x + 3y -2 = 0, P1(5,2)
A=4, B=3, C= -2, x1=5, y1=2
L1 : A(x-x1)+B(y-y1)=0
L1 : 4(x-5)+3(y-2)=0
L1 : 4x -20 + 3y -6 =0
L1 : 4x + 3y - 26 =0
check: substitute x=5, y=2
4(5)+3(2)-26 = 20+6-26=0
Therefore L1 passes through P1.
Slope: m = -4/3
b. Line L2 perpendicular to L
L : 4x + 3y -2 = 0, P1(5,2)
A=4, B=3, C= -2, x1=5, y1=2
L2 : B(x-x1)-A(y-y1)=0
L2 : 3(x-5) - 4(y-2) = 0
L2 : 3x -15 - 4y + 8 = 0
L2 : 3x - 4y - 7 = 0
check: substitute x=5, y=2
L2 : 3(5)-4*2-7 = 15-8-7=0 L2 passes through P1.
ok this is a problem similar to it correct
Related Questions
Write an equation in the indicated form for each statement described below.
(A graph shows two li...
let L1 be the line throught (1,-6,2) with direction vector (1,2,1) and L2 be the line throught (0,4,...
write the equation of the line that passes throught the point (3,-1) and is parallel to the line y =...
write an equation for the line that is parallel to the given line and passes throught the given poin...