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Asked by Anonymous

Write in general form - ax^2+bx+c

Vertex: (-1,-1)
point on the graph: (0,4)
11 years ago

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Answered by Steve
we know that
y = a(x+1)-1
4 = a(1)-1
so a = 5

y = 5(x+1)-1
y = 5x^2 + 10x + 4
11 years ago
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Write in general form - ax^2+bx+c

Vertex: (-1,-1)
point on the graph: (0,4)

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