Asked by Dee
Suppose f and g are functions that are differentiable at x=1 and that f(1)= 2, f'(1)= -1, g(1)= -2, and g'(1)= 3. Find the value of h'(1).
h(x)= [x f(x)] / [ x + g(x) ]
h(x)= [x f(x)] / [ x + g(x) ]
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Answered by
Dee
I figured it out myself. Thanks anyways.
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