Question

Suppose f and g are functions that are differentiable at x=1 and that f(1)= 2, f'(1)= -1, g(1)= -2, and g'(1)= 3. Find the value of h'(1).

h(x)= [x f(x)] / [ x + g(x) ]

Answer 1

I figured it out myself. Thanks anyways.