To graph the line with a given point and slope, "slope-intercept form" (y = mx + b) can be used.
Given:
Point: (1, -1)
Slope: 3/2
Step 1: Substitute the values of the point and slope into the equation (y = mx + b):
-1 = (3/2)(1) + b
Step 2: Solve for the y-intercept (b):
-1 = 3/2 + b
b = -1 - 3/2
b = -2.5/2 - 3/2
b = -5.5/2
Step 3: Substitute the slope and y-intercept back into the equation to get the final equation of the line:
y = (3/2)x - 5.5/2
The final equation of the line is y = (3/2)x - 5.5/2
Now, we can graph the line:
- Choose a few x values (for example, -2, 0, and 2) and substitute them into the equation to find the corresponding y values.
- Plot the points (x, y).
- Connect the points with a straight line to complete the graph.
Here is the graph of the line:
*[illustration line_graph]
Graph the line with the given point and slope.
The line through (1,negative 1) with slope 3/2
1 answer