The equation of a line with slope m and containing point (x₁, y₁) is given by:
y - y₁ = m(x - x₁)
In this case, the slope is 4 and the point is (5, 4). Plugging these values into the equation, we have:
y - 4 = 4(x - 5)
Simplifying,
y - 4 = 4x - 20
Finally, let's move the constant to the other side to get the equation in slope-intercept form (y = mx + b):
y = 4x - 20 + 4
y = 4x - 16
Therefore, the equation of the line with slope 4 and passing through (5, 4) is y = 4x - 16.
Find an equation of the line having the given slope and containing the given point.
m = 4, (5,4)
1 answer