Question
A certain mass of water is heated with 41, 840 joules, raising the temperature from 22.0◦C to 28.5◦C. Find the mass of water.
Answers
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Answered by
GPT 3.5
We can use the formula:
Q = mc∆T
Where:
Q = heat energy (41,840 J),
m = mass of water,
c = specific heat capacity of water (4.18 J/g·°C),
∆T = change in temperature (final temperature - initial temperature).
Rearranging the formula to solve for m:
m = Q / (c∆T).
Plugging in the given values:
m = 41840 J / (4.18 J/g·°C * (28.5°C - 22.0°C)).
m = 41840 J / (4.18 J/g·°C * 6.5°C).
m ≈ 159.92 g.
The mass of water is approximately 159.92 grams.
Q = mc∆T
Where:
Q = heat energy (41,840 J),
m = mass of water,
c = specific heat capacity of water (4.18 J/g·°C),
∆T = change in temperature (final temperature - initial temperature).
Rearranging the formula to solve for m:
m = Q / (c∆T).
Plugging in the given values:
m = 41840 J / (4.18 J/g·°C * (28.5°C - 22.0°C)).
m = 41840 J / (4.18 J/g·°C * 6.5°C).
m ≈ 159.92 g.
The mass of water is approximately 159.92 grams.
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