Asked by LeAnne
You wish to heat 30 kg of water from 60°C to 80°C. How many kcal of heat are necessary to do this? To how many kJ does this correspond?
Answers
Answered by
Elena
1 kJ = 0.24 kcal
c=4186 J/kg•K
Q=cmΔT
c=4186 J/kg•K
Q=cmΔT
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