Question

140 Cal to heat 355 gm of water with initial temperature of 25 degree celsius, final temp?

Answer 1

140=355*1cal/gram*(t-25)
solve for Temp t

Answer 2

It's 140 Kcal. I got Tf 419.4 deg C. This seemed very high and I can't figure out error

Answer 3

it wont go that high, water boils.
your calculations are correct, but something is wrong with the problem statement, either in the kcal, or the mass.

Answer 4

It's a can of coke problem.... 355 ml of water (assume coke=water)140 Cal in the can. Using energy from sugar in can. What final temp would be reached if initial was 25 deg C. ?

Answer 5

so my question is Cal. is that calories, or Calories (ie, Food Calories=1 kcal).
a) if it is food, then the water heats up to 100C, then boils , and if all of it boils away, the residual heat heats the steam. This is harder. You have to figure the heat of vaporization at 100C, and the specific heat of steam.
If it is calories, then it is the way I suggested.

Answer 6

I think it's a crappy question, a and b section of introduction question all talk about teaspoons of sucrose and calories associated. That leads one to believe we are dealing with nutritional Calorie = 1000 calories right? I don't think it's a heat of vaporization cause we haven't covered that yet. only on ch 6 in open stax text. Any thoughts