Asked by B.B.
Did I do this problem correctly?
Solve the following system by first handling the equation of the two lines:
x=(0, 2) y=(-2, 1)
x=(0, -1) y=(-3, -2)
Equation 1: y= -x1
Equation 2: y=4x/3+2T
Is this the correct answer?
Solve the following system by first handling the equation of the two lines:
x=(0, 2) y=(-2, 1)
x=(0, -1) y=(-3, -2)
Equation 1: y= -x1
Equation 2: y=4x/3+2T
Is this the correct answer?
Answers
Answered by
bobpursley
No, neither is correct.
m= (y1-y2)/(x1-x2)
m= (y1-y2)/(x1-x2)
Answered by
drwls
The slope of the first line is (using BobPursley's formula)
[1 -(-2)]/2 = 3/2
The y-intercept (where x=0) is -2.
Therefore the equation is y = 3x/2 - 2
Now you do the other line.
[1 -(-2)]/2 = 3/2
The y-intercept (where x=0) is -2.
Therefore the equation is y = 3x/2 - 2
Now you do the other line.
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