You number is correct; if you obtained it correctly from your work I can't tell.
mass percent = (mass solute/100 g solution)*100
[(18.6)/(18.6 + 81.4)]*100 =
(18.6/100)*100 = 18.6%
Did I do this correctly or do I need to try again?
What is the mass percent of a solution when 18.6 g of table salt is added to 81.4 g of water?
Mass Percent = mass of solute(g)x100
mass of solution (g)
= 18.6 g x100
18.6 g + 81.4g
= 18.6 g x 100
100g
= 0.186 x 100
= 18.6
The mass percent of the solution is 18.6%
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