Question

Water was added to 120•0g of a salt, mcl^2 to produce 60•0 cm^3 of a saturated solution at 25°c its solubility at 25°c is 8•0 dm^-3 calculate the mass of the salt which remained undissolved

Answer 1

To solve this problem, we need to first calculate the amount of salt that actually dissolved in the saturated solution. We can use the given solubility and the volume of the solution.

Solubility of the salt at 25°C = 8.0 dm^-3

Volume of the solution = 60.0 cm^3 = 0.06 dm^3

Mass of the salt dissolved = Solubility x Volume of the solution
= 8.0 dm^-3 x 0.06 dm^3
= 0.48 g

Next, we need to find the mass of the salt that remained undissolved.

Total mass of the salt = Initial mass of the salt - Mass of the salt dissolved

Initial mass of the salt = 120.0 g

Mass of the salt remained undissolved = 120.0 g - 0.48 g
= 119.52 g

Therefore, the mass of the salt which remained undissolved is 119.52 g.