Asked by mustafa
How much water must be added to 200 g of a 10% NaOH solution to obtain 8%
solution
solution
Answers
Answered by
bobpursley
you are diluting it 10/8 times=1.25 times.
That means, one part original solution, and .25 parts water.
that means then add 50 grams water.
check:
original salt mass=20g
new salt mass=.08*250=20g
That means, one part original solution, and .25 parts water.
that means then add 50 grams water.
check:
original salt mass=20g
new salt mass=.08*250=20g
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.