How much water must be added to 200 g of a 10% NaOH solution to obtain 8%

solution

1 answer

you are diluting it 10/8 times=1.25 times.
That means, one part original solution, and .25 parts water.

that means then add 50 grams water.

check:
original salt mass=20g
new salt mass=.08*250=20g