Asked by Winston Churchill

4.00L of water was added to 0.400L of an aqueous ethanol solution, giving a final concentration of 0.0400 M. What is the initial concentration of ethanol?

I just need help setting it up pls

Thanks!
Answered by Winston Churchill
Never mind I figured it out!
Answered by bobpursley
you diluted it by a factor of 11, with one part original, ten parts water.

Then, if the final concentration is.04M, the initial must have been .44M (11 times the final)

Want to do it with Math?

final solute= initial solute
.04M*4.4L=?*.4L

?= .44M