Asked by Siphelo
A body starting from rest, travels a distance of 45 meters during the fifth second of motion.Calculate the acceleration of the body
Answers
Answered by
Siphelo
v=u=at
Answered by
bobpursley
d(6)-d(5)= 45
1/2 a (6^2-5^2)=45
surely you can solve for a.
1/2 a (6^2-5^2)=45
surely you can solve for a.
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