Question

A car starts from rest and travels along a circular track with a radius of 55.0 meters. The car starts out at a position due East of the center of the track, heading due North initially around the track, which is counterclockwise. The car increases its speed by 105 m/s every minute around the track. What is the cars acceleration towards the center of the track when it is 1/4 of the way around the track?

Answer 1

v^2=u^2+2as
v^2=2as
2pi*r/4=86.35

v^2=302.225

centripetal acceleration=v^2/r=5.49