d = (1/2) a t^2
since they ask only for distance, a magnitude, and not final position, a vector, you do not have to give a negative sign for the distance.
d = (1/2) (1.3)(5.6)^2
= 20.4 meters
A car starts from rest and travels for 5.6 s
with a uniform deceleration of 1.3 m/s
2
.
What is the final velocity of the car?
Answer in units of m/s
I know the answer for this is -7.28
but I cant figure out how to the second part.
How far does the car travel in this time interval?
Answer in units of m
1 answer
1 answer