Question

A stone of mass 0.7kg is projected vertically upward with a speed of 5ms.calculate the maximum height reached.(Neglect air resistance and take g, as 10ms

Answer 1

To calculate the maximum height reached by the stone, we can use the kinematic equation:

v^2 = u^2 + 2as

Where:
v is the final velocity (0 m/s at the maximum height, as the stone stops moving)
u is the initial velocity (5 m/s)
a is the acceleration (acceleration due to gravity, g = 10 m/s^2)
s is the displacement (maximum height, which is what we want to find)

Rearranging the equation to solve for s:

s = (v^2 - u^2) / (2a)

Plugging in the given values:

s = (0^2 - 5^2) / (2 * -10)

s = (-25) / (-20)

s = 1.25 meters

Therefore, the maximum height reached by the stone is 1.25 meters.