Asked by samuel
A stone of mass 0.7kg is projected vertically upward with a speed of 5m/s.calculate the maximum height reached. [Take g=10m/s^2 and neglect air resistance].
"
"
Answers
Answered by
Henry
V^2 = Vo^2 + 2g*h, V = 0, Vo = 5m/s, g = -10m/s^2, h = ?.
Answered by
Judith
a baseball is thrown vertically upward with an initial speed of 20m/s .calculate how fast it was travelling on its way down when caught 5.0m above where it was thrown.
Answered by
zaadat
2.8
Answered by
AyodejiGB¥
The appropriate formular is..
H=u(square)/2g..
height=U square(initial vel.) /divided by 2g
so,_H=5sqr /2*10.
Therefore;-25 /20..which is equare to 1.25m. ans(1.25 m).
H=u(square)/2g..
height=U square(initial vel.) /divided by 2g
so,_H=5sqr /2*10.
Therefore;-25 /20..which is equare to 1.25m. ans(1.25 m).
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.