Vo = 5 m/s = Initial velocity.
V = 0 = Final velocity = Velocity at max. ht.
g = -10 m/s.
V^2 = Vo^2 + 2g*h. h = ?.
A stone of mass 2.8kg is projected upward with a speed of 5m/s. calculate the maximum height reached. use g=10m/s square.
3 answers
The answer is 22.3m for the maximum height.
0 = 5^2 - 2*10*h,
20h = 25, h = 1.25 m.
A 2nd method:
V = Vo + g*t
0 = 5 -10t, t = 0.5 s.
h = Vo*t + 0.5g*t^2,
h = 5*0.5 - 5*0.5^2,
h = 2.5 - 1.25 = 1.25 m.
A 3rd Method:
KE = PE.
0.5M*Vo^2 = Mg*h
1.4*5^2 = 2.8*10*h
35 = 28h, h = 1.25 m.
Based on the information given, your answer is incorrect.
20h = 25, h = 1.25 m.
A 2nd method:
V = Vo + g*t
0 = 5 -10t, t = 0.5 s.
h = Vo*t + 0.5g*t^2,
h = 5*0.5 - 5*0.5^2,
h = 2.5 - 1.25 = 1.25 m.
A 3rd Method:
KE = PE.
0.5M*Vo^2 = Mg*h
1.4*5^2 = 2.8*10*h
35 = 28h, h = 1.25 m.
Based on the information given, your answer is incorrect.
4 answers