Question

Find the surface area of a rectangular pyramid with these measurements: l = 8 yd., w = 4 yd.,
and h = 2 yd. (1 point)
• 72.52 yd.2
• 43.31 yd.?
• 66 yd.?
• 55.55 yd.?

Answer 1

To find the surface area of a rectangular pyramid, we need to find the area of each of its faces and add them up.

1. The base of the pyramid is a rectangle with dimensions 8 yd. by 4 yd. The area of the base is length times width, so the area of the base is 8 yd. times 4 yd. which equals 32 square yards.

2. The other four faces of the pyramid are triangles. Each of these triangles has a base equal to the width of the rectangle (4 yd.) and a height equal to the height of the pyramid (2 yd.). We can find the area of each triangle using the formula for the area of a triangle, which is 1/2 times base times height. Therefore, the area of each triangle is 1/2 times 4 yd. times 2 yd., which equals 4 square yards.

Since there are four triangles, the sum of their areas is 4 times 4 square yards, which equals 16 square yards.

Finally, we can add up the area of the base (32 sq. yd.) and the sum of the areas of the four triangles (16 sq. yd.) to find the total surface area of the rectangular pyramid.

32 sq. yd. + 16 sq. yd. = 48 sq. yd.

Therefore, the surface area of the rectangular pyramid is 48 square yards.

None of the given answer options match the correct answer.