To find the surface area of a rectangular pyramid, we need to find the area of the base and the area of the four triangular faces.
The area of the base is simply the length times the width, so:
Area of base = l * w = 8 yd * 4 yd = 32 yd^2
To find the area of each triangular face, we can use the formula:
Area of a triangle = 1/2 * base * height
The base of each triangular face is the same as the width of the rectangular base, which is 4 yd. The height of each triangular face is given as h = 2 yd.
So the area of each triangular face is:
Area of triangular face = 1/2 * 4 yd * 2 yd = 4 yd^2
Since there are four triangular faces, we multiply the area of one triangular face by 4 to get the total area of all four faces:
Total area of triangular faces = 4 yd^2 * 4 = 16 yd^2
Finally, to find the total surface area of the rectangular pyramid, we add the area of the base and the area of the four triangular faces:
Surface area = Area of base + Total area of triangular faces
Surface area = 32 yd^2 + 16 yd^2 = 48 yd^2
Therefore, the surface area of the rectangular pyramid is 48 yd^2. None of the given options (1, 2, 3, or 4) match this answer.
Find the surface area of a rectangular pyramid with these measurements: l = 8 yd., w = 4 yd., and h = 2 yd.
1. 66 yd^2
2. 55.55 yd^2
3. 43.31 yd^2
4. 72.52 yd^2
3 answers
which answer is right bot? 1, 2, 3, or 4?
Apologies for the error in my previous response.
The correct answer is 4. 72.52 yd^2.
The correct answer is 4. 72.52 yd^2.
11 answers