Question
Find the surface area of a rectangular pyramid with these measurements: l = 8yd , w = 4yd , and h = 2 yd. (1 point) 66yd .^ 2; 43.31v * d ^ 2; 55.55yd .^ 2; 72.52v * d ^ 2
Answers
GPT 3.5
To find the surface area of a rectangular pyramid, we need to find the area of each face and add them up.
The base of the rectangular pyramid is a rectangle with dimensions length (l) and width (w). So, the area of the base is l * w = 8yd * 4yd = 32yd^2.
The other four faces of the pyramid are triangles. To find the area of each triangle, we can use the formula: area = 0.5 * base * height.
The base of each triangle is the width (w) of the base rectangle, which is 4yd. The height of each triangle is the height (h) of the pyramid, which is 2yd.
So, the area of each triangle is 0.5 * 4yd * 2yd = 4yd^2.
Since there are four triangular faces, the total area of the triangular faces is 4 * 4yd^2 = 16yd^2.
Finally, to find the surface area of the pyramid, we add the area of the base and the area of the triangular faces: 32yd^2 + 16yd^2 = 48yd^2.
Therefore, the surface area of the rectangular pyramid is 48yd^2.
None of the given options (66yd^2, 43.31v*d^2, 55.55yd^2, 72.52v*d^2) matches the correct surface area.
The base of the rectangular pyramid is a rectangle with dimensions length (l) and width (w). So, the area of the base is l * w = 8yd * 4yd = 32yd^2.
The other four faces of the pyramid are triangles. To find the area of each triangle, we can use the formula: area = 0.5 * base * height.
The base of each triangle is the width (w) of the base rectangle, which is 4yd. The height of each triangle is the height (h) of the pyramid, which is 2yd.
So, the area of each triangle is 0.5 * 4yd * 2yd = 4yd^2.
Since there are four triangular faces, the total area of the triangular faces is 4 * 4yd^2 = 16yd^2.
Finally, to find the surface area of the pyramid, we add the area of the base and the area of the triangular faces: 32yd^2 + 16yd^2 = 48yd^2.
Therefore, the surface area of the rectangular pyramid is 48yd^2.
None of the given options (66yd^2, 43.31v*d^2, 55.55yd^2, 72.52v*d^2) matches the correct surface area.