Question

Given the quadratic equation y=5x^2+8x+9, solve for the y-coordinate of the parabola when x=−3.(1 point)
(−3, )

Answer 1

To find the y-coordinate of the parabola when x = -3, we substitute -3 for x in the equation y = 5x^2 + 8x + 9.

y = 5(-3)^2 + 8(-3) + 9
y = 5(9) - 24 + 9
y = 45 - 24 + 9
y = 30

Therefore, the y-coordinate of the parabola when x = -3 is 30.

So, (-3, 30)