Question

find the surface area of a rectangular pyramid with these measurements: I = 8 yd, w = 4 yd, and h = 2 yd.
a 72.2 yd^2
b 43.31 yd^2
c 55.55 yd^2
d 66 yd^2

Answer 1

The surface area of a rectangular pyramid can be found by adding the area of the base to the sum of the areas of the four triangular faces.

The area of the base can be found by multiplying the length and width: 8 yd * 4 yd = 32 yd^2.

To find the area of each triangular face, we can use the formula A = (1/2) * base * height. The base of each triangular face is the width of the rectangular base (4 yd) and the height is the height of the pyramid (2 yd). So the area of each triangular face is (1/2) * 4 yd * 2 yd = 4 yd^2.

There are four triangular faces, so the total area of all four is 4 yd^2 * 4 = 16 yd^2.

Finally, we add the area of the base (32 yd^2) to the area of the four triangular faces (16 yd^2) to find the total surface area of the pyramid: 32 yd^2 + 16 yd^2 = 48 yd^2.

None of the given answer choices match the calculated surface area of 48 yd^2.