Find the surface area of a rectangular pyramid with these measurements: l

= 8 yd., w
= 4 yd., and h
= 2 yd.(1 point)
Responses

66 yd.2
66 yd. 2

43.31 yd.2
43.31 yd. 2

55.55 yd.2
55.55 yd. 2

72.52 yd.2

3 answers

The formula for the surface area of a rectangular pyramid is:

Surface Area = Base Area + (1/2) * Perimeter of Base * Slant Height

First, let's find the base area. The base of the pyramid is a rectangle, so the area is:

Base Area = length * width = 8 yd. * 4 yd. = 32 yd.²

Next, let's find the perimeter of the base. The base of the pyramid is a rectangle, so the perimeter is:

Perimeter of Base = 2 * (length + width) = 2 * (8 yd. + 4 yd.) = 2 * 12 yd. = 24 yd.

Finally, let's find the slant height. Since this is a right rectangular pyramid, the slant height can be found using the Pythagorean Theorem:

slant height² = height² + (base/2)²
slant height² = 2 yd.² + (4 yd./2)²
slant height² = 2 yd.² + 2 yd.²
slant height² = 4 yd.²
slant height = √(4 yd.²)
slant height = 2 yd.

Now, we can substitute these values into the surface area formula:

Surface Area = 32 yd.² + (1/2) * 24 yd. * 2 yd.
Surface Area = 32 yd.² + 12 yd. * 2 yd.
Surface Area = 32 yd.² + 24 yd.²
Surface Area = 56 yd.²

The correct answer is 56 yd.².
choose either one of the answers above
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