Asked by Sunshine
                what volume of 0.4 M HCl is required to neutralize 100.0 mL of 0.3 M LiOH?
            
            
        Answers
                    Answered by
            DrBob222
            
    For a 1:1 ratio of acid to base, which you have, mL x M = mL x M.
mL(HCl) x 0.4 M = mL(LiOH) x 0.3 M
Solve for mL(HCl).
    
mL(HCl) x 0.4 M = mL(LiOH) x 0.3 M
Solve for mL(HCl).
                    Answered by
            OSA
            
    (ii)	If 22.0 mL of 2.5 M HCl was used to neutralize 50.0 mL of a Ba(OH)2 solution, what was the concentration of the base? 
    
                    Answered by
            Anonymous
            
    75 ml of hcl
    
                    Answered by
            Tesfa
            
    0.6
    
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