Question

Find the centroid of the triangle with the vertices P(-3,1), Q(3,4), R(3,-2)

Answer 1

To find the centroid of a triangle, we need to find the average of the x-coordinates and the average of the y-coordinates of the vertices.

Let's first find the average of the x-coordinates:
x-coordinate of P = -3
x-coordinate of Q = 3
x-coordinate of R = 3

Average of x-coordinates = (-3 + 3 + 3)/3 = 3/3 = 1

Now let's find the average of the y-coordinates:
y-coordinate of P = 1
y-coordinate of Q = 4
y-coordinate of R = -2

Average of y-coordinates = (1 + 4 + (-2))/3 = 3/3 = 1

Therefore, the centroid of the triangle with vertices P(-3,1), Q(3,4), and R(3,-2) is (1,1).