Ask a New Question

Asked by AJ

Find the centroid of the region bounded by the curve sin x on the interval (0, pi) and the x-axis.

Please help
14 years ago

Answers

Answered by Mgraph
Let C(x,y)-centroid. Obviously, x=pi/2
The area of the region=2
y=(1/2)(1/2)(integral from 0 to pi) sin^2(x)dx=pi/8
14 years ago

Related Questions

find the centroid of the region bounded by x^2-12x and the x-axis How do you find the centroid of the coordinates D(-3, 8), E(-3, 0) and F(9, 4). What are the steps? Find the centroid for an area defined by the equations: y=2x+4 and y=((2x-3)^2)+1 find the centroid of the plane region bounded by the curves y = cos x, y=sinx, x=0, Find the centroid of the region bounded by the given curves. y = 2 sin 3x, y = 2 cos 3x, x =... Find the centroid of the region in the first quadrant bounded by the x-axis, the parabola y^2 = 2x,... Find the centroid (x¯,y¯)(x¯,y¯) of the region bounded by: y=5x^2+6x y=0 x=0 x=6 I know the int... Find the centroid (¯ x, ¯ y) of the region bounded by: y = 6x^2+7x, y = 0, x = 0, and x = 7 Find the centroid of the region in the first quadrant bounded by the x-axis, the parabola v ^ 2 = 2x... find the centroid from a (5,5), b (1,7), and c (3,2) in this formula: x1+x2+x3/3, y1+y2+y3/3) ans...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use