Asked by Gertrude

4x^2+12 = 0

I factored this out, but how do I show the final answer? Thanks!

4(x^2+3)

Answers

Answered by MathMate
4(x<sup>2</sup>+3)=0
x<sup>2</sup>=-3
x=sqrt(-3)
=±(sqrt(3)*i)
where i<sup>2</sup>=-1
The roots are therefore complex.
Answered by Gertrude
Would iroot3 and -iroot3 be acceptable answers? Thanks!
Answered by MathMate
Yes, they are acceptable answers.

When in doubt (as in an exam), the best way to check an answer is to square your proposed roots and see if you get back -3.



Answered by Gertrude
Thanks for the help!
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