Asked by Gertrude
4x^2+12 = 0
I factored this out, but how do I show the final answer? Thanks!
4(x^2+3)
I factored this out, but how do I show the final answer? Thanks!
4(x^2+3)
Answers
Answered by
MathMate
4(x<sup>2</sup>+3)=0
x<sup>2</sup>=-3
x=sqrt(-3)
=±(sqrt(3)*i)
where i<sup>2</sup>=-1
The roots are therefore complex.
x<sup>2</sup>=-3
x=sqrt(-3)
=±(sqrt(3)*i)
where i<sup>2</sup>=-1
The roots are therefore complex.
Answered by
Gertrude
Would iroot3 and -iroot3 be acceptable answers? Thanks!
Answered by
MathMate
Yes, they are acceptable answers.
When in doubt (as in an exam), the best way to check an answer is to square your proposed roots and see if you get back -3.
When in doubt (as in an exam), the best way to check an answer is to square your proposed roots and see if you get back -3.
Answered by
Gertrude
Thanks for the help!
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