225/88ra arrow 2/4he+221/blank rn

Question

The missing box would be the number and this is a form of decay.

Blank 1:
Blank 2:

Answer 1

To solve the nuclear reaction provided:

\[ \frac{225}{88} \text{Ra} \rightarrow \frac{2}{4} \text{He} + \frac{?}{?} \text{Rn} \]

1. Identify the missing values:

   • The element \(\text{Rn}\) (Radon) has an atomic number of 86.
   • First, we need to check the mass number before and after the decay.

   Before decay:
   Mass number of Ra = 225

   After decay:
   Mass number of \(\text{He}\) = 4
   Let the mass number of \(\text{Rn}\) be \(A\).

   According to the law of conservation of mass number: \[ 225 = 4 + A \ A = 225 - 4 = 221 \]

   Now, check the atomic number:

   • Atomic number of Ra = 88
   • Atomic number of He = 2
   • Let the atomic number of Rn be \(Z\) (which is 86).

   According to the law of conservation of atomic number: \[ 88 = 2 + Z \ Z = 88 - 2 = 86 \]

2. Conclusion:

   • The missing box would have the values: \(\frac{221}{86} \text{Rn}\).
   • The decay process here is alpha decay (since \(\text{He}\) is the alpha particle).

Therefore, the answers would be:

Blank 1: 221
Blank 2: alpha decay